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X^2+10X-85.25=0
a = 1; b = 10; c = -85.25;
Δ = b2-4ac
Δ = 102-4·1·(-85.25)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-21}{2*1}=\frac{-31}{2} =-15+1/2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+21}{2*1}=\frac{11}{2} =5+1/2 $
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